Simplify this Boolean expression: $(BC'+A'D)(AB'+CD')$.

Question

I need to simplify this Boolean expression: $(BC'+A'D)(AB'+CD')$

I'm unsure what the theorems say about this. But I've tried this, and not sure if this is the right way: $BC'AB' + BC'CD' + A'DAB' +A'DCD'$ ...and this is ezpz.

Answer 1

For a boolean variable $X$, $XX'=0$, since either $X$ or $X'$ must be $0$. This can be used to solve your expanded expression.