Simplifying $(-2x^2 y^{-1} )^3 / 2y^{-2}$, with positive exponents

Question

The question is $$(-2x^2 y^{-1} )^3 / 2y^{-2} $$

I did it till $$-4x^6 y^{-1}$$ I'm told to put it in a form of positive indices . Can I say that the answer is $x^6 / 4y$ ?

Answer 1

Close, but do it as

$$-4x^6 / y.$$

You can't get rid of the minus in front of 4, but this is alright, as you only want the exponents to be positive.