I have to simplify $\neg(s \wedge(t \vee u ) \wedge ((s \wedge t) \rightarrow u))$
I started by trying to using $(p \rightarrow q) \iff \neg p \vee q$ and DeMorgan's laws but things got messy. Any suggestions?
I have to simplify $\neg(s \wedge(t \vee u ) \wedge ((s \wedge t) \rightarrow u))$
I started by trying to using $(p \rightarrow q) \iff \neg p \vee q$ and DeMorgan's laws but things got messy. Any suggestions?
DeMorgan is the way to start. You have a negated conjunction, which becomes the disjunction of the negation of the terms. Then a negated implication becomes a conjunction (of what?)