I have to show that the following expression are equal using the simplification rules:
$$x' y z + x y' z + x y z' + x' y z' + x y' z' + x' y' z = x y' + y z' + z x'$$
But I can only get to:
$$y'z + y'x + x' y z$$
Please let me know what I am doing wrong here. I don't know how to proceed from here.
2026-03-26 19:03:52.1774551832
Simplifying Boolean expression.
48 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
Use:
Adjacency
$pq + pq'=p$
In other words: look for pairs of terms that have all literals in common except one.
Thus, the first and sixth term simplify to:
$x'yz+x'y'z=x'z$
The second and fifth and also be combined:
$xy'z+xy'z'=xy'$
And finally, the third and fourth:
$xyz'+x'yz'=yz'$
So, the whole thing simplifies to:
$x'z+xy'+yz'$