Simplifying $R_1R_2R_3 + R_1R_2R_4 + R_1R_3R_4 + R_2R_3R_4$ pattern

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Consider this sum of inverses:

$$\frac{1}{f_n} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \cdots + \frac{1}{R_{n}}$$

The sum can be "simplified" with summation symbol:

$$\frac{1}{f_n} = \sum_{i=1}^n\frac{1}{R_{i}}$$

I want to compute $f$ and express the above formula in terms of summation symbol(s).

Consider $n = 3$ case:

$$\begin{align*}f_n &= \frac{R_1R_2 + R_1R_3 + R_2R_3}{R_{1}R_{2}R_{3}} \\ &= \frac{\color{red}{?}}{\prod_{i=1}^n R_i}\end{align*}$$

I am not sure how to express the $\color{red}{?}$ numerator in terms of, probably, summation symbol(s).

There is a pattern for sure.

Consider $n = 4$:

$$f_n = \frac{\overbrace{\overbrace{R_{1}R_{2}R_{3}}^{n-1 \text{ terms}} + \overbrace{R_{1}R_{2}R_{4}}^{n-1 \text{ terms}} + \overbrace{R_{1}R_{3}R_{4}}^{n-1 \text{ terms}} + \overbrace{R_{2}R_{3}R_{4}}^{n-1 \text{ terms}}}^{n \text{ terms}}}{\prod_{i=1}^{n} R_{i}}$$

Would anyone be able to help me formalize this numerator for $n \in \mathbb{Z}^{+}$?