Simplifying the following expression algebraically

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This is for a class on logic gates and boolean expressions, the expression I was given is the following:

$$x'y'z'+w'x'yz'+wx'yz'$$

I have done one other question like this so far and I struggled with it, so far I have only been able to do the following:

$$x'z'(y'+w'y+wy)$$

I'm not entirely sure if I'm even allowed to remove the common elements the way I did here but it was the first thing I noticed, after that I did the following:

$$x'z'(y' + y)$$

I know that $w'y+wy = y$ so I placed that there and I know that $y + y'$ is always true so the final answer I arrived at was:

$$ x'z'$$

I don't know exactly if everything I did is allowed, and I couldn't find an answer online either. Could someone confirm if I was able to do this question properly or point out to me where I messed up. Thank you very much

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You correctly notice you can collect $x'z'$; this leaves to simplify $$ y'+w'y+wy=y'+y(w'+w)=y'+y1=y'+y=1 $$ so what remains is indeed $x'z'$.