The problem:
I need to use Error Bound to find n (least) to the $10^{-9}$ in approximating the integral of 5e^x^2 from 0 to 1
I'm using
$$Error(Sn) \le \frac{k(b-a)^5}{180N^4}$$
I found the 4th Derivative to be:
$$ Error^{(4)}(Sn)= 20e^{x^2}(4x^4 + 12x^2 + 13)$$
The max I found to be at 1, so
$$\frac{8060e}{180n^4} \le 0.000,000,001$$
solve for n
$$\left(\frac{8060e}{180\cdot0.000,000,001}\right)^{\frac 14} \le n$$
$$n = 590$$
Is this true? I don't think it is the correct answer, but I'm not sure where my error is
I made a math mistake.
The f''''(1) = 360e (not 8060e)