I'm stuck solving what appears to be a simple simultaneous equation. A point in the right direction would be appreciated.
Solve the simultaneous equations for x and y:
$y=x^{2}+7x-11$,
$y=x-1$
my workings: $0=x^{2}+6x-10$
$10=x^{2}+6x$
$10/x=x+6$
From here i go around in circles trying to solve for $x$. I'm sure i've missed something basic. Thank you in advance.
On
There are two equations $$ \begin{align} y_{1}(x) &= x^{2} + 7x - 11 \\ y_{2}(x) &= x - 1 \end{align} $$
Equate them $y_{1}(x) = y_{2}(x)$ and solve for $x$.
You are looking for the roots of $$ y(x) = x^{2}+6x-10 $$ They are $$ x_{\pm} = -3 \pm \sqrt{19} \approx \left(-7.3589, 1.3589 \right) $$
Once you have $x^2+6x-10=0$, you have a standard quadratic equation.
Solve it.