If $x^3=a+1$ and $x+(b/x)=a$ Then $x$ equals?? Please help in solving these equations. I can't get it how to solve $1$ variable by two equations
2026-04-26 03:00:37.1777172437
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Simultaneous Linear Equations for single variable
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You have actually three unknowns and only two equation so the value of $x$ is not unique. One has for example, the integer solutions (which is not necessary) $$(x,a,b)=(2,7,35),(1,0,-1),(3,26,69)$$ and infinitely many more (take a value of $a$ such that $a+1$ be a cube so you have a value for $x$ and a value for $b$).
Notice that $x+\dfrac{b}{x}=a$ is equivalent to $x^2=ax-b$. Now multiplying this by $x$ yields $$a+1=x^3=ax^2-bx=a(ax-b)-bx=(a^2-b)x-ab,$$ and thus $x=\dfrac{1+a+ab}{a^2-b}$. Note that there must be some conditions on $a$ and $b$ for this to hold!