Sine as derivative of cosine and vice versa.

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The derivative of the sine of angle is the cosine of the same angle. Depending on which book you look at or which teacher you ask or which website you're looking at, I've seen it as derivative of sine is negative cosine, derivative of cosine is negative sine, or as stated above, sine is derivative of cosine. (At least, I'm pretty sure I've seen all of those exprssions) Aren't all of these equal?

Secondly, since the sine and cosine values are 90 degrees out of phase with each other (meaning that they are perpendicular) and since the definition of derivative requires that the slope at the point of tangency be perpendicular and that lines (slopes in this case) are perpendicular if and only if the products of their slopes are negative 1 isn't it intuitive to deduce that the derivative of the sine is negative cosine and the derivative of the cosine is negative sine?

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The nice thing about trigonometric functions is that taking the derivative shifts the curve 90 degrees to the left. Sine and cosine each have 360 degree symmetry, and 180 degree reverse symmetry, so taking two derivatives always gets you the negative of the original function, and taking four gets you the original function back. Because $\cos$ is just $\sin$ shifted 90 degrees to the left, this gets you all the information you need.