Draft the set $\{z||z-2|>|z-3|\}$ in the complex plane. What I did is: $\{z|\sqrt{(x-2)^2+y^2}>\sqrt{(x-3)^2+y^2}\}=\{z|(x-2)^2>(x-3)^2\}=\{z|x>2.5\}$. Now how is such a set "sketched"? It really seems to me like a Locus but I haven't practiced it since I graduated High-School and now I was given it after the first lecture with no background regarding Sketching. Do I simply mark the entire right side of the Axis system? I would appreciate your help.
2025-01-13 06:03:25.1736748205
Sketch the set $\{z||z-2|>|z-3|\}$ in the complex plane.
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Let $z=x+iy$ such that $x>2.5$
So you can color the region right side of the line $x=2.5$ excluding the line.