Smooth of $d(x_0,exp_x(v))$ and injectivity radius.

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According to this question, the curvature can't control the injectivity radius. So, I don't know why support of $\varphi(v)$ need be small compared to maximum curvature? I think it should be compared to injectivity radius for keeping $f(x)$ is smooth.

Picture below is from the 210 page of this paper.

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