Smooth $r$-form as the exterior product of $r$ $1$-forms

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Let $M$ be a $n$-dimensional manifold and $\alpha$ a smooth $r$-form in $M$. It is clear that $\alpha$ can be written locally as $\alpha=\alpha_1\wedge \ldots \wedge \alpha_r$ for some $1$-forms $\alpha_1,\ldots,\alpha_r$ just by considering its expression in a local chart of $M$.

In general, can we have this descomposition $\alpha=\alpha_1\wedge \ldots \wedge \alpha_r$ in the whole manifold? Maybe with the use of bump functions?

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In looking for the easiest counter example, my initial answer was incorrect. However, it is still not true, even locally. For example, if we take $dx\wedge dy+dz\wedge dw$ on $\mathbb{R}^4$, you cannot write this as a wedge of $1$-forms, but trying to is probably a good exercise.