Can anyone solve for $t$ the equation: $$ e^t=\frac{1-nt}{1-t} $$
with $n \in \mathbb N$ (known) and $t>0$. Online solvers give an answer only for specific values of $n$, but I need a general formula for $t$.
Thanks.
Can anyone solve for $t$ the equation: $$ e^t=\frac{1-nt}{1-t} $$
with $n \in \mathbb N$ (known) and $t>0$. Online solvers give an answer only for specific values of $n$, but I need a general formula for $t$.
Thanks.
In this special case, you can guess t = 0 as a solution.
This solution is, moreover, independent from n.
Perhaps the solution can be found by expanding the right side of the equation. It is a geometric series (up to a constant).
The expansion of the right side is
$$1 + (1-n) (t+t^2+t^3+t^4+...)$$