How do we solve $$\Pi(y(x)+1)+\sin(x)=y(x)+y'(x)$$ I suspect it will be a function of many cases. The solution of $$\Pi(x+1)+\sin(x)=y(x)+y'(x)$$ is hard only at the evaluation of the last integral which requires 3 cases, but what happens if $y(x)$ is in the rectangular function?
2026-03-31 03:33:33.1774928013
Solution of $\Pi(y(x)+1)+\sin(x)=y(x)+y'(x)$
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