Calculate $$\left(\sum_{k=0}^{5}\left(3k-10\right)\right)\prod_{r=1}^{4}r$$
So what I did first is expand each notation as it is, so
$$\left(\sum_{k=0}^{5}\left(3k-10\right)\right)\prod_{r=1}^{4}r = (-10-7-4-1+2+5) \cdot (1\cdot 2\cdot 3\cdot 4)= -15\cdot 24 = -360$$
Can anyone help me verify this is correct? Thank you.
Yes, your answer is correct and your steps make sense.
As further evidence, Wolfram Alpha also gets the same answer
Making this a community wiki answer since I don't really have anything else to add beyond a "yes, you're right."