I am trying to find all integer solutions to the following equation: $$32x^2 - y^2 = 448$$
This is what I have tried so far:
The equation describes a hyperbola, and so I try the usual trick of intersecting the curve with a line of rational slope to find rational solutions first.
Knowing the point (4,8) satisfies the equation, I solve the following system: $$\left\{ \begin{array}{c} 32x^2 - y^2 = 448 \\ y = m(x - 4) + 8 \\ \end{array} \right.$$
After a bunch of algebra, I get: $$x = \frac{-4m^2+16m-128}{32-m^2}$$ $$y = \frac{8m^2-256m+256}{32-m^2}$$
Finally, substituting $m = \frac{u}{v}$, I get: $$x = \frac{-4u^2+16uv-128v^2}{32v^2-u^2}$$ $$y = \frac{8u^2-256uv+256v^2}{32v^2-u^2}$$
Cool, with any choice of $u$ and $v$, I get a rational solution.
But since cancelling the denominators does not work, I do not know how to continue to get integer solutions only.
Is this perhaps not the right way to go? Any help would be much appreciated.
$y^2$ divisible by $64$.
Let $y=8y_1$.
Thus, we have $$x^2-2y_1^2=14,$$ which says that $x$ divisible by $2$.
Let $x=2x_1$.
Thus, we need to solve $$2x_1^2-y_1^2=7,$$ which reduce to Pell.
https://en.wikipedia.org/wiki/Pell%27s_equation