Solve for $x$ where: $$x^2=2^x$$
Graphing the function ($f(x)=x^2-2^x$) it is clear that there are three solutions.
Two of them are nice solutions. i.e. $x=2,4$
The graph shows a third solution at $x=-0.76666...$
I found this using the Newton-Raphson method but it took quite a few iterations.
What other methods are there for solving such a question?