Solve $g(x + \frac{1}{x}) = x^y + \frac{1}{x^y}$

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Let $y$ be a real number.

Find $g$ such that

$$g(x + \frac{1}{x}) = x^y + \frac{1}{x^y}$$

Is valid for all real $x$.

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Setting $x=e^u$ one gets $$g(2\cosh(u))=2\cosh(u·y)$$ which resolves to $$ g(z)=2\cosh(y·\text{Arcosh}(z/2)) $$ for all $z\ge 2$