Solve $\int_{0}^{\infty} a^{ix^2}$ dx with contour integration?

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Evaluate $$\int_{0}^{\infty} a^{ix^2} dx$$ for $0<a<1$ using contour integration methods.

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$$a^{ix^2}=\left(e^{\ln a}\right)^{ix^2}$$ so you have: $$I=\int_0^\infty e^{i\ln(a)x^2}dx$$ then I'd suggest using the substitution $u=\sqrt{\ln(a)}x$