Solve the equation $xu_x+tu_y=-tu$ with $u(x,0)=x$

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Using the characteristic method to solve

$$xu_x+uu_y=-tu, \quad\infty <x<\infty\;\; t>1\\ u(x,o)=x$$

here $\frac{dx}{x}=\frac{dt}{t}=-\frac{u}{t}$

Consider $\frac{dt}{t}=-\frac{u}{t}\implies t=-u+c_1$

now consider $\frac{dx}{x}=\frac{u}{-t}=\frac{du}{c_1-u}\implies x=c_2(c_1-u)$

Since $u(x,0)=x\implies x=s,t=0,u=s$

From I'm unable to eliminate the constants any help?

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I always found it easier to write the characteristic equations in parametrized form: $$\frac{dx}{ds}=x,\quad x(0)=r$$ $$\frac{dy}{ds}=u,\quad y(0)=0$$ $$\frac{du}{ds}=-tu,\quad u(0)=r$$ This gives $x(s)=re^s, u(s)=re^{-ts}$ immediately, with the ODE for $y$ being $$\frac{dy}{ds}=re^{-ts}.$$ Once you solve this, you can find $s$ and $r$ in terms of $x$ and $y$, allowing you to express $u$ in terms of $x$ and $y$, which is the solution of the original PDE.