Solve the following trigonometric exercise...

Question

Can you please give a hint how to solve this exercise:

$$\log(\tan 22)+ \log(\tan 68)=?\\ \tan22\cdot\tan68=?$$

Thank you!

Answer 1

Hint In degree $$\tan(90-x)=\frac{1}{\tan x}$$

Answer 2

HINT:

$$22^\circ=90^\circ-68^\circ$$ and $$\tan(90^\circ-x)=\cot x$$

also $$\tan22^\circ\cdot\tan68^\circ\ne0$$