Solve the simultaneus equations
$ab$ + $c$ + $d$ = $3$
$bc$ + $d$ + $a$ = $5$
$cd$ + $a$ + $b$ = $2$
$da$ + $b$ + $c$ = $6$, where $a$,$b$,$c$,$d$ are real numbers.
I tried to add all of them and factor them as $xy$ + $x$ + $y$ = $(x+1)(y+1)$ - $1$. Thank you for your responses.
Assuming the last was supposed to be $da+b+c=6$ from the symmetry of the variables, Alpha finds $a=2, b=c=0, d=3$ which is easy to verify. It can also solve the problem as written, but the solutions are not as clean.