Solve the triangle $PQR$ where.
$q=2.9\text{ m}$
$r = 3.5\text{ m}$
$\angle LQ = 25^{\circ}$
Does the $\overline{LQ}$ mean right angle triangle?
Should I use $3.5 \text{ m}$ as the hypotenuse?
Solve the triangle $PQR$ where.
$q=2.9\text{ m}$
$r = 3.5\text{ m}$
$\angle LQ = 25^{\circ}$
Does the $\overline{LQ}$ mean right angle triangle?
Should I use $3.5 \text{ m}$ as the hypotenuse?
Though it is not clear which angle is 25 deg. considering angle Q as 25 deg. and given that PQ=3.5 & PR=2.9 hence sin(Q) = PR/PQ [as you want consider PQ as Hypotenuse hence angle R is 90 deg] for Right angle triangle but as you can see it is not same. Also if we assume that somehow angle P is 90 deg then tan(Q)=PR/PQ which is again not same. Hence this triangle can not be a right angle triangle.