Solve the triangle trigonometry.

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Solve the triangle $PQR$ where.

$q=2.9\text{ m}$

$r = 3.5\text{ m}$

$\angle LQ = 25^{\circ}$

Does the $\overline{LQ}$ mean right angle triangle?

Should I use $3.5 \text{ m}$ as the hypotenuse?

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Though it is not clear which angle is 25 deg. considering angle Q as 25 deg. and given that PQ=3.5 & PR=2.9 hence sin(Q) = PR/PQ [as you want consider PQ as Hypotenuse hence angle R is 90 deg] for Right angle triangle but as you can see it is not same. Also if we assume that somehow angle P is 90 deg then tan(Q)=PR/PQ which is again not same. Hence this triangle can not be a right angle triangle.