Solve this inequality $e^{-x} + 2e^{-x/2} > 1$. According to WolframAlpha, it's $x < 2\log(1 + \sqrt{2})$. How does one get this?
2026-04-07 22:06:23.1775599583
Solve this inequality $e^{-x} + 2e^{-x/2} > 1$.
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Hint
$$y=e^{-x/2}\\ y^2+2y>1$$