Solve $(x+7)^2+\sqrt{y-8}=0$

200 Views Asked by At

I need help for solving the following equation :

$$(x+7)^2+\sqrt{y-8}=0$$

I already got $(x=-7),(y=8)$ as the answer, but it isn't clear enough. A simple explanation or another solution would help me.

1

There are 1 best solutions below

3
On BEST ANSWER

$$(x+7)^2=-\sqrt{y-8}$$

LHS $\ge 0$ and RHS $\le 0$

Equality occurs only when : LHS $=$ RHS $=0$

$$\implies x=-7 , y=8$$