I need help for solving the following equation :
$$(x+7)^2+\sqrt{y-8}=0$$
I already got $(x=-7),(y=8)$ as the answer, but it isn't clear enough. A simple explanation or another solution would help me.
I need help for solving the following equation :
$$(x+7)^2+\sqrt{y-8}=0$$
I already got $(x=-7),(y=8)$ as the answer, but it isn't clear enough. A simple explanation or another solution would help me.
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$$(x+7)^2=-\sqrt{y-8}$$
LHS $\ge 0$ and RHS $\le 0$
Equality occurs only when : LHS $=$ RHS $=0$
$$\implies x=-7 , y=8$$