Solve $x = \sqrt[x]2$

Question

How does one solve $x = \sqrt[x]2$ for $x$? This can be otherwise stated as

$x = 2^{1/x}$

Raising both sides to the power of $x$:

$x^x = (2^{1/x})^x$
$x^x = 2$

But I don't know where I can go from here.