1) Find an equation for the line with vector form <5,-2>, + t<2,6> in the form y = mx + b
For this I had no idea how to do
2) Find the value of k such that <-2,k> is the vector of the line with the equation y = (4x+1)/7
For this one I thought that k was equal to -1 after plugging -2 in for x but it's incorrect.
Plz help, thank you
Hint:
If a line is given by $\langle x,y\rangle=\langle p,q\rangle+t\langle a,b\rangle$,
then two points on the line $(t=0$ and $t=1)$ are $\langle p,q\rangle$ and $\langle p+a,q+b\rangle$,
so the slope of the line is $\dfrac{(q+b)-q}{(p+a)-p}=\dfrac ba$.