from the second equation we get $$y+|y-5|=6$$
if $$y\geq 5$$ we have $$2y-5=0$$ thus $$y=\frac{11}{2}$$
if $$y<5$$ we have $$y-y+5=6$$ there is no solution in this case.
computing $x$ we get the following solution set
$$x=\frac{3}{2},y=\frac{11}{2}$$
or
$$x=\frac{1}{2},y=\frac{11}{2}$$
2
Bumbble Comm
On
Hint:
Apply this rule: Suppose $f(x)=|x-k|$, then $f(x)$ can be decomposed into:
$$
f(x)=
\begin{cases}
x-k, & \text{when } x>k;\\
0, & \text{when }x=k;\\
-(x-k), & \text{when }x<k.
\end{cases}
$$
from the second equation we get $$y+|y-5|=6$$ if $$y\geq 5$$ we have $$2y-5=0$$ thus $$y=\frac{11}{2}$$ if $$y<5$$ we have $$y-y+5=6$$ there is no solution in this case. computing $x$ we get the following solution set $$x=\frac{3}{2},y=\frac{11}{2}$$ or $$x=\frac{1}{2},y=\frac{11}{2}$$