$\ddot y(t)+2\dot y(t)+2y(t)=5H(t-2\pi)sint$
Also, $y(0)=1$ and $\dot y(0)=0$
I took the usual approach of solving an initial value problem but things get a bit tricky after the first few steps due to involvement of Heaviside's function.
Any help is appreciated.
Hint:) \begin{eqnarray*} && {\cal L}(y^{\prime\prime})+2{\cal L}(y^{\prime})+2{\cal L}(y)={\cal L}(5H(t-2\pi)\sin t) \\ && s^2{\cal L}(y)-sy(0)-y^\prime(0)+2\Big(s{\cal L}(y)-y(0)\Big)+2{\cal L}(y)=5\dfrac{e^{-2\pi s}}{s^2+1} \\ && {\cal L}(y)\Big(s^2+2s+2\Big)=5\dfrac{e^{-2\pi s}}{s^2+1}+s+2 \\ && {\cal L}(y)=5\dfrac{e^{-2\pi s}}{(s^2+1)(s^2+2s+2)}+\frac{s+2}{s^2+2s+2} \end{eqnarray*} Now using partial-fraction decomposition continue!