I know that: $$\frac{T_2}{T_1} = e^{\mu_s \pi}$$ $$\tau = (T_2-T_I)R$$
why:
$$T_1 = \frac{\tau}{R}*\frac{1}{e^{\mu_s \pi}-1}$$
I was trying to put t_2 from the second eq to the first then solve for t_1 but this didnt work:
do I have enought data or I am missing something
You have that $$T_2=T_1 e^{μ_s π}$$ so substituting that to the second equation gives you: $$τ=(T_2-T_1)R=(T_1 e^{μ_s π}-T_1)R=(e^{μ_s π}-1)T_1R$$ Dividing by $(e^{μ_s π}-1)R$ yields: $$T_1=\frac{τ}{R}*\frac{1}{(e^{μ_s π}-1)}$$ as wanted.