A triangle has the side lengths shown below. Find the length of each side, if the length of AC exceeds that of AB by $\frac{1}{2}$.
What I did:
$3x + 1 +\frac{1}{2}= 6x - 4 $
$6x - 3x = -4 - 1 - 1/2$
$3x = -5.5$
$x = -1.8333...$
But when I substitute I get the wrong answer.
Thank You and help is appreciated
Since the length of the side AC exceeds AB of 1/2 it means that AC is AB+1/2. Therefore the right equation is
$$3x+1=6x-4+1/2$$ You get x=3/2