$(27^{x - 1})(3^x) = 9^{2x-3}$. I apologize if you do not understand the equation. I was unsure on how exactly to represent it correctly. I have gotten to the step in the equation where it is $3^{4x-3} = 3^{4x-6}$ and then you set the exponents equal to each other, so $4x-3=4x-6$ but my teacher did not explain what happens when the $x$'s cancel and they will clearly cancel in this equation. So if anyone can tell me what to do next, it would be greatly appreciated!
2026-04-03 03:52:29.1775188349
solving exponential functions
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After cancelling the $4x$ term from both sides, we find that $-3 = -6$, a contradiction. So the equation has no solution. That is, if you plot each side of the equation separately, then the curves won't intersect.