A wheel is rotating at 3 radians per second and the wheel has an 80 inch diameter To the nearest foot per minute, what is the linear velocity?
2026-03-29 04:11:47.1774757507
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Solving for linear velocity
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The radius is $40 \text{ inches} = \frac{40}{12} \text{ feet}= \frac{10}3 \text{ ft}$ since $12 \text{ inches}=1\text{ foot}$. The wheel every second moves a distance equal to the arc length subtended by a $3$ radian angle on the wheel. The arc length is given by $3\cdot \frac{10}3\text{ feet}=10\text{ ft}$. So it moves $10 \text{ feet}$ in one second. The distance it moves in $1$ minute shouldn't be difficult to find.
V=r*W
where V= linear velocity, r= radius and W=angular velocity
but first you need to convert inches to foot
r= 40 inches = 10/3 foot
now V= r*W = 10/3 * 3 = 10 foot per sec
V= 600 foot per min
are you from US because never heard of using foot/min