How do I solve equations like $$kx = 9k^2 +4k+4$$
I can solve for $x$ but am unable to do it for $k$. Anyone can explain it to me?
2026-04-29 23:05:08.1777503908
Solving quadratic equation in two variables
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$$9k^2+(4−x)k+4=0$$ $$D=(4-x)^2-4\cdot 9 \cdot 4=16-8x+x^2-144=x^2-8x-128$$ $$k_{1,2}=\frac{x-4 \pm \sqrt{x^2-8x-128}}{18}$$ real solutions exist when $x^2-8x-128\ge 0$ ($x \in (-\infty; -8]\cup[16;\infty)$)