I am trying to make a website that runs off of this equation. I am only in algebra but I am trying to solve a systems of equation where instead of solving for $x$ and $y$ I am solving for $m$ and $b$. Here is the equation:
$$100,333.333333=m10.3333333+b$$ $$6000=(m10.333333+b)-(m5+b)$$
I solved this by solving it the same way you would solve for $x$ and $y$ and I got:
$1125=m$
$-1291.66666666=b$
For the equation to work perfectly it would be best if I could make both $m$ and $b$ positive. Is there any way that I could make it so that the equation is true but both $m$ and $b$ are positive?
Thank you for your response!
A linear system of equations either has zero solutions, one solution or infinitely many solutions. So no, you can't find another value of $b$.