Solving the following equation by factorisation

Question

The given equation is,

$\frac{m}{n}x^2+\frac{n}{m}=1-2x$

What I've tried,

Multiplying the equation by $n$, we get

$mx^2+\frac{n^2}{m}x=n-2nx$

Now what? I am completely confused about what to do. Have I followed the correct steps?

Answer 1

multiply by $\frac{m}{n}$ on both sides, you get

$(\frac{m}{n})^2 x^2+1=(1-2x)\frac{m}{n}$

$(\frac{m}{n})^2 x^2+2x\frac{m}{n} + 1 -\frac{m}{n}=0$

$(\frac{mx}{n})^2+2(\frac{mx}{n}) + (1 -\frac{m}{n})=0$

can you see you got a quadratic equation in $\frac{mx}{n}$?

Do quadratic formula here then divide by $\frac{m}{n}$ and you got what x equals to