Solve for $(x,y)$: \begin{align} y &= x\\ y &= (1-40x)^{-1/51.33}-1\ \end{align}
I don't know if finding a closed-form solution is possible, have been trying for almost half an hour but still get nothing.
Please tell me some idea about how to solving it, or if it is possible to do.
Edit: I did manage to get the answer via Geogebra, but I would love to see how people solve it analytically.
$$y = x \land y = (1-40x)^{-1/51.33}-1\\ \implies (1-40x)^{-1/51.33}-x=1\\ \implies \frac{1}{(1 - 40 x)^{1/51.33}} = x+ 1 \qquad 40x\ne1\\ \implies 1=(x+ 1)(1 - 40 x)^{1/51.33} \\ $$ At this point I must defer to WolframAlpha here for $\quad x=y=0\land x=y = 0.00999525$