How do you solve $y'-\frac y x=0$ the answer should be $y=ex$ but I can't get to that point. I tried using the integrating factor but I can't get it to add up.
2026-03-30 08:31:26.1774859486
Solving $y'-\frac y x=0$ with integrating factor
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You may have made a mistake in computing an integrating factor, but one such factor is $ 1/x$. Multiplying the equation by $1/x$ and using product rule, we obtain $(y/x)' = 0$. So $y/x = C$, where $C$ is a constant. In other words, $y = Cx$.