So this might be very easy but I can't seem to think properly right now,
I'm trying to solve for $w$.
I have $$ z = \frac{w(i-1)}{i(w-1)}$$
where $i$ is an imaginary number.
What would $w$ be?
So this might be very easy but I can't seem to think properly right now,
I'm trying to solve for $w$.
I have $$ z = \frac{w(i-1)}{i(w-1)}$$
where $i$ is an imaginary number.
What would $w$ be?
Hint
Rewrite the equation as: $$z \cdot i(w-1)=w(i-1)$$ i.e $$w\left((i-1)-iz\right)=-iz$$