Solving $ z = \frac{w(i-1)}{i(w-1)}$

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So this might be very easy but I can't seem to think properly right now,

I'm trying to solve for $w$.

I have $$ z = \frac{w(i-1)}{i(w-1)}$$

where $i$ is an imaginary number.

What would $w$ be?

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Hint

Rewrite the equation as: $$z \cdot i(w-1)=w(i-1)$$ i.e $$w\left((i-1)-iz\right)=-iz$$