Speed to break a rock climbing quick draw

Question

I have a quickdraw (a lifesaving device used during rock climbing). It has a strength rating of 22kN (4945.8 pounds force). Assuming I weigh 200 lbs and slow/decelerate over 1 second, how fast would I have to be moving to break the quickdraw?

Answer 1

Using impulse of the force and assuming the rope is ideal and your initial velocity is zero, you'd want the resulting force on the rope to be: $$F_{avg} \lt 22000N = m·a_{avg}=m\frac {\Delta v} {\Delta t} \approx \frac {90.7kg} {1s}·v \Rightarrow v \lt 242.6m/s$$

so a speed greater than approximately $242.6m/s$ will likely break the quickdraw.