Splitting field of a polynomial has a solvable group of automorphisms

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Prove that splitting field of a polynomial $f \in \mathbb{k}[x]$ ($f = 0$ solvable by radicals) has a solvable group of automorphisms $Aut_\mathbb{k}(\mathbb{F})$.

I have just started learning Galois theory, any advice will be highly appreciated. Thanks in advance.