The problem States:
Given $\bar x= 41$ and $\bar y= 40.7$.
$σ_x= 0.1$ and $σ_y= 0.19$
$X \sim N[\mu_X; \sigma^2]; Y \sim N[\mu_Y ; \sigma^2]$; with $\mu_X > 0,\; \mu_Y > 0, \sigma > 0$ and $\theta = µ_X - µ_Y$ .
The two samples are independently distributed and have $n_X = n_Y = 18$. Now it asks me to find the point estimate for $\theta$ and its standard deviation.
The point estimate is simply $\hat{θ} = \bar x − \bar y = 41 − 40.7 = 0.3$
Now I have no idea how to find the standard deviation..can't find any similar example on my book or on google. The solution I'm given is: Standard deviation = $0.05$
