Stokes Theorem: Unit Ball

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Given the unit ball: $$M:=\mathbb{B}:\quad\partial M=\varnothing$$

Consider the top-degree form: $$\omega:=1\mathrm{d}x\wedge\mathrm{d}y=\mathrm{d}(x\mathrm{d}y)=:\mathrm{d}\Omega$$

Then one has by Stoke's theorem: $$\pi=\int_\mathbb{B}1=\int_\varnothing\Omega=0$$ But where is the flaw??

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The problem is that the form is not compactly-supported.

Also as soon as one introduces a positive bump it fails to have a primitive.