Let $A$ be a $C^*$-algebra.
$a\in A^+$ is strictly positive in $A$ if $\overline{aAa}=A$
*I know that if $A$ is unital, $a\in A^+$ is strictly positive iff $a\in Inv(A)$
Q1:Let $A:=C_0(0,1)$. Is there any strictly positive element is$A$?why?
Q2:Let $A$ be non-unital. Is there any condition (like *) for $a\in A^+$ such that $a$ is strictly positive ?
Let $a(t)>0$ for all $t\in (0,1)$ (eg $1-2|t-1/2|$). Then for each $n \in \mathbb{N}$, there exists a function $c_n \in C_0(0,1)$ so that $c_n(t)a(t)=1$ whenever $t \in I_n :=[\frac{1}{n},1-\frac{1}{n}]$. This consideration shows that for any $f \in C_0(0,1)$ $(a c_n f c_n a)(t)=f(t)$ whenever $t \in I_n$. The construction implies that $f \in \overline{aAa}$. (Where $\lim_{t\to 0/1}f(t)=0$ is necessary for the convergence of the sequence in sup-norm sense).
Since any function that is always positive has hermitian root functions, whenever $a(t)>0$ for all $t$, then $a \in A^+$ and as such $a$ is actually strictly positive. In fact only if a function in $C_0(0,1)$ has strictly positive range is it strictly positive in the $C^*$ algebra sense.
In this script there are some equivalent notions of when elements are strictly positive. Specifically if $a \in A^+$ then $\overline{aAa}=A \iff \overline{aA}=A \iff \left(\frac{a}{||a||}\right)^{1/n}$ is an approximate identity.