Subspace of a weakly sequentially complete is weakly sequentially complete

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A Banach space $X$ is called weakly sequentially complete if all weakly Cauchy sequences are weakly convergent.

Question: If $Y$ is a subspace of a Banach space $X$, must $Y$ be weakly sequentially complete?

My guess is yes, but I don't know how to prove it.

Any hint is much appreciated.