I always wondered but never understood how to solve the following type of equation $$\begin{matrix} &{x}+y=35 \\ &x\geq15 \\ &y\geq 15 \\ &(x,y) \in \mathbb{N} \end{matrix} $$
(I just made up values) I found the two pairs $$(19;16) \;\& \;(17;18)$$ Are they the only solutions ? if they are, how to prove it?

You can write $ x=15+k_1, y =15+k_2$ Now substitute these in $ x+y =35 $ We get $ k_1 + k_2 =5 $ Now the number of possible values of $k_1, k_2$ corresponds to the possible values of $x$ and $y$ so the number of ways are $ C(n+r-1,r-1) $ Here, in this particular problem $n=5$ and $r=2$, so total ways are $6$.