$ \sum_{p } \sum_{k=2}^{\infty} \frac{\log p}{p^k}$ is Convergent

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How can I show the sum $ \sum_{p } \sum_{k=2}^{\infty} \frac{\log p}{p^k}$ where $p$ varies over all the primes, is Convergent?

I tried comparing with the convergent series $\sum_{p} \frac{1}{p^2}$, but it doesn't seem to work.

Any help would be appreciated. Thanks in advance.