summation of a series in which each term is product of nth term of two sequence

Question

Is it possible to find the sum $\Sigma_{x=1}^n ((2x)(4x+1))$? If yes then can somebody please explain for me the formula?

Answer 1

There are well-known formulas for $\sum_{k=1}^n k^2=\frac{n(n+1)(2n+1)}6$, $\sum_{k=1}^n k=\frac{n(n+1)}{2}$, $\sum_{k=1}^n 1=n$, from which you can combine your result.