Suppose $f,g\in \sqrt{I} \subseteq K[x]$ such that $in(f)>in(g)$. Then $g\in I$.

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In reference to this answer. I'm guessing it has something to do with being able to find some elements in I with the same initial terms as f and g, and then canceling out leading terms somehow, but I have no idea how to approach it, and haven't been able to find it in either of the textbooks I have access to.